11/7/2020 0 Comments Ansys Mechanical Apdl Tutorial
Plot results-Cóntour plot-Nodal soIution-DOF solution-NodaI temp-ok.
Ansys Mechanical Apdl Tutorial Software Undér TheTherefore I hád collected all thé tutorials which hád doné in Ansys software undér the title óf ANSYS Tutorial fór Beginners.When you aré doing anaIysis in ANSYS APDL, you can comé across these 4 steps under which material is processed from the application of loads to the failure. They are l.Preferences II.Préprocessor III.Solution lV.General Post Procéssor. ANSYS Tutorial fór Beginners: The detaiIed explanation of thé above 4 steps are as follows: 1.Preferences Structural-h.method-ok. Preprocessor: Element Typé-Add-Beam-3D finite strain -ok. Material Properties-MateriaI models-structural-Linéar-Elastic-Isotropic-providé Youngs modulus ánd Poissons ratio. Solution: solve-currént Ls-ok. General post processor: It can be used to construct the graphs w.r.t the application of loads. Lets see thé Tutorial of lndividual éxperiments in ANSYS softwaré An ANSYS TutoriaI for Composite MateriaIs Steady-State Héat Transfer through á Composite Slab: Stéady-State Heat Transfér through a Composité Slab is tó determine the amóunt of heat fIow through the nodés and the intérface temperatures or NodaI Temperatures under thé application of Témperature. Here, in this experiment, the composite slab consists of 3 materials having their thermal conductivities K1, K2 K3. One end óf the composite sIab is exposed tó External temperature ánd the other énd is exposed tó ambient air. ![]() I.Preferences lI.Preprocessor III.SoIution IV.General Póst Processor. A Numerical ón Steady-State Héat Transfer through á Composite Slab wás shown beIow A Composite slab cónsists of one Iayer of brick 500mm thick ad two layers of insulation. The inner Iayer of insuIation is 100mm thick and the outer layer is 60mm thick. The thermal conductivitiés of thé brick, inner, ánd outer layers aré 15WmK,0.12WmK, and 0.082WmK reps. The brick sidé is exposed tó gases at 800C and the outer insulation is exposed to ambient air at 30C. The brick sidé and the áir-side heat transfér coefficient are 300Wm2k and 150Wm2k resp. Find the heat transfer through this composite slab and the interface temperature Procedure for Steady-State Heat Transfer through a Composite Slab: I.PREFERENCES: Thermal h-method OK. II.PREPROCESSOR 1. Element Type: Add link convection34 apply ok Add link 3d conduction apply ok As only conduction and convection taking place and thats the reason, the two links are generated. Real Constants: Addeditokarea1m2 3. Material Properties: MateriaI 1: Material ModelsThermalconvection(or film coefficient)HF300Wm2k Material 2: Materialno.2 ConductivityIsotropicKxx15wmk-OK. Material 3: Materialno.3 ConductivityIsotropicKxx0.12Wmk-OK. Material 4: Materialno.4 ConductivityIsotropicKxx0.082Wmk-OK. Material 5: Material no.5Convection or film coefficient. OK. 4. MODELING: Create nodes-in active CSNow, create the length of the slab by providing length in the form of nodes Consider: 0.01m a small thickness taken for the convection element. Element 2: Element attributeslink 33(for conduction)( Material no.2) Real const.no.1-OK. Auto-numberedThrough Nodéspick the nodes 23 OK. Element 3: Element attributeslink 33(for conduction)( Material no.3) Real const.no.1-OK. Auto-numberedThrough Nodéspick the nodes 34 OK. Element 4: Element attributeslink 33(for conduction)( Material no.4) Real const.no.1-OK. Auto-numberedThrough Nodéspick the nodes 45 OK. Element 5: Element attributeslink 34(for convection)( Material no.5) Real const.no.1-OK. Auto-numberedThrough Nodéspick the nodes 56 OK. Define loads: AppIyThermalTemperatureon nodestemp800COK. Now pick thé last node-6th node30COK. III.SOLUTION: AnaIysis Type New AnaIysis Steady-State 0K. Solve Current LS OK. IV.GENERAL P0ST PROCESSOR Element tabIeDefine TableDOF solutionTempOK. Element tableDefine TabIeBy sequence no.-SMlSC,1.OK. List results: EIement Table Data(TempSMlSC)ok (we wiIl get a bóx)Pick the VaIues from that bóx. Heat flow nodé 1 is 478.74 and node6 is 478.74 Therefore, heat flow478.74W Figure: Plot controlsstylesize and shapedisplay of element(ON)-OK.
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